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Re^2: How to sub class-esby exilepanda (Friar) |
on May 15, 2020 at 11:42 UTC ( [id://11116812]=note: print w/replies, xml ) | Need Help?? |
Thank you so much for remind me that it is not an is-a condition, but has-a. Totally agree with that. Perhaps I should ask "how to do has-a correctly" =) And I've added the code into my post.
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