Re: Advent of Code, Day 15, golfed!

[tybalt89]

Quick golf trick: push() has a return value :)
Replace push@a,/./g;$r||=@a with $r||=push@a,/./g and save 3 strokes.
UPDATE: Oops. that what I get for not testing :(

Alternates:

push@a,@r=/./g}{print$s{-1+map{$u{$_}||=$a[$_]+$s{$g-1}for
grep$a[$_]*!$s{$_},$g+@r,$g-!!($g%@r),$g-@r*($g>=@r),++$g*!!($g
%@r);($g)=sort{$u{$a}-$u{$b}}keys%u;$s{$g}=delete$u{$g}}@a}

and

# problem description says "resembles a square"
push@a,/./g}{print$s{-1+map{$u{$_}||=$a[$_]+$s{$g-1}for
grep$a[$_]*!$s{$_},$g+$.,$g-!!($g%$.),$g-$.*($g>=$.),++$g*!!($g
%$.);($g)=sort{$u{$a}-$u{$b}}keys%u;$s{$g}=delete$u{$g}}@a}

[Jasper]

I don't think that will work because only the first row will be pushed into @a.

[Jasper]

Combining that with another stroke saved by replacing the stupid ++$g, $g-1 stuff

push@a,/./g}{print$s{-1+map{$u{$_}||=$a[$_]+$s{$g}for
grep$a[$_]*!$s{$_},$g+$.,$g-($g%$.>0),$g-$.*($g>=$.),$g+($g%$.
<$.-1);($g)=sort{$u{$a}-$u{$b}}keys%u;$s{$g}=delete$u{$g}}@a}

[Jasper]

$. definitely works, how could I forget! :)