Re^2: Why does eof have a prototype?

[LanX]

> IMHO the first sentence doesn't apply here because eof's syntax can be expressed by a prototype

Depends how you define "syntax can be expressed by a prototype".

A "can be parsed without errors" criteria is not enough for me.

eof(); and eof; are (magically) different syntax for eof, and this difference can't be expressed with prototypes.

In the past the prototype symbol set was extended with *, + or _ in order to add prototypes to other built-ins.

This criteria isn't met here.