Re^6: converting binary to decimal

[LanX]

> I even have problems to reproduce my own explanation in the debugger.

And the reason is that it's supposed to be a "bitstring" not "numeric bit" operation.

see https://perldoc.perl.org/perlop#Bitwise-String-Operators

hence replacing | with |. under use feature "bitwise" will stop doing hard to predict things, even after refactoring this golfing code.

ugh...

[tybalt89]

That's why the original code very intentionally |'s together two results of the (higher precedence) concatenation operator '.' - which always produces a "string" and not a "number".

voodoo89 tybalt89

[LanX]

guess what, refactoring fails,

      my $copy1b = '0' . $copy1;
      my $copy2b = $copy2 . $_;
      
      $n = ($copy1b | $copy2b);

copying it literally into the debugger too

  DB<38> say (0 . "$_" | 1 . "1") for qw/0 2 4 6 8/ 
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The only fix is using |. and use feature 'bitwise';

  DB<39> use feature 'bitwise'; say (0 . "$_" |. 1 . "1") for qw/0 2 4
+ 6 8/ 
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> voodoo89

Yeah, now go back and sacrifice 89 more chickens to the god of golf ;-P

[tybalt89]

Er, Umm, no.

$ perl -le 'print(0 . $_ | 1 . 1) for qw/0 2 4 6 8/'
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Most probable reason you are seeing what you saw -> you did "use feature 'bitwise'" earlier in your debugging session. 'bitwise' forces plain | to numeric.

voodoo89 tybalt89 looks around for more chickens...