Re: 1 line array to hash converter

[suaveant]

Almost!

@hash{@array} = (1) x scalar(@array};

need to put an @ at the front... not sure why, but you do

                - Ant
                - Some of my best work - Fish Dinner

[jeffa]

The @ sign pretty much tells the interpreter to expect a SLICE, and since hash is (hopefully) already defined as a hash, you get a hash slice. :)

japhy has a great little 'tutorial' i found (via google) at http://www.crusoe.net/~jeffp/docs/using_refs

jeffa

[davorg]

Actually, it's the type of brackets - {} - that tells Perl that's it's a hash slice.

--
<http://www.dave.org.uk>

"The first rule of Perl club is you don't talk about Perl club."

[Sifmole]

Just because your statement confused me a little:

The type of brackets - {} - tells Perl that it's a hash.
The @ tells Perl to use list context vs. scalar context.

Note the difference between:

@hash{@array} = (1) x scalar(@array);
print join(" -- ", keys %hash), "\n";

#AND

$hash{@array} = (1) x scalar(@array);
print join(" -- ", keys %hash), "\n";

[clintp]

Nit: useless use of scalar

@hash{@array}=(1) x @array;

Works peachy as well.