How to include a string immediately after a variable in a double-quoted string

[msh210]

Hi, Monks,

I have a bunch of scalar variables to include in a string. In order to avoid a bunch of ugly concatenation dots, I include them all in a double-quoted string. So far, so good. But one of the variables is to be followed, within the string, by some (non-variable alphanumeric) text. Obviously, I can't just concatenate them within the double-quoted string. Two options I can think of are:

1. print "The maximum number of $type" . "events on $date occurred $maxtimes times; it was $max.\n";
2. print "The maximum number of $type$\events on $date occurred $maxtimes times; it was $max.\n";   if $\ is undefined

But I don't much like either of those. The first is a bit ugly/inelegant to my mind: I prefer one long double-quoted string. The second is dependent on a variable that may change in a later revision of the script; plus, it's distasteful to me because there's nothing tying $\ to this string semantically.

Is there a more elegant way of doing this? Or is my option 1 (or 2?) considered elegant enough?

[dave_the_m]

print "The maximum number of ${type}events on $date occurred $maxtimes times; it was $max.\n";


Dave.

[jeffa]

You can also use printf/sprintf to keep your data separated from the "presentation":

printf "The maximum number of %sevents on %s occurred %d times; it was
+ %d.\n",
    $type,
    $date,
    $maxtimes,
    $max,
;

[stevieb]

I always forget about printf in Perl. In Python (3+), there's no interpolation, so I'd have to do print("Hello {}, how are you {}".format(name, today)).

No matter what you want to print with variables, you have to do it this way (at least for a normal print statement), including all the parens and cruft.

I've taken perl interpolation for granted me thinks ;)

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[msh210]

Thank you!

[stevieb]

Interpolating inner braces ("${var}") to the rescue!!!

perl -E '$x="hi "; say "${x}there"'
hi there

[msh210]

Thank you, dave_the_m, stevieb!