Re: perl experts .. plz

[davido]

• The input captured into $verb will probably end in a newline. You should use chomp to rid your string of that unwanted clutter.
• Your split statement splits into void context (the return value is not captured), and the parameters are wrong; you certainly don't want to treat $verb as a pattern.
• Your for statement increments $i before entering the loop, and never again. The $i++ should appear after the last semicolon, not before the first one.
• Your second print statement includes $verb-3, which will result in -3 being printed, and if warnings are enabled, a warning being generated, because $verb will probably not contain anything resembling a number, so Perl will treat it as a zero in numeric context.
• You are using @pronouns_ending to hold two types of data in a confusing way. Better to use an array of array-refs, or some data structure that better reflects the relationships of the data that are currently only represented by partitioning the array.
• You lack a final }, preventing compilation.
• You aren't using strict and warnings -- tools that will aid in preventing or discovering other common pitfalls.

[blueberry]

thank you Mr. davido, but again i don't get it .. it's supposed to be an easy question i know, but honestly am very week in perl.. would u plz help me correct and creat a script out of this:( using loop for) #.............................# @pronouns_ending=("i","you","he/she/it","we","you","they","","","","s","",""); print"Give a verb to be conjugated in present simple :\n\nVerb:\t"; $verb=<<>>; split $verb; print "\n"; for($i++;$i<4;){ print pop(@pronouns_endings)." ".$verb-3.shift(@pronouns_endings)."\n"; }

[blueberry]

Mr. Dave i tried to follow your instructions and that's what i got #..................# use strict; use warning; @pronouns_ending=("i","you","he/she/it","you","they","","","s","",""); print"remember :\n\nVerb:\t"; chomp $verb=<<>>; split $verb; print "\n"; for($i++;$i<4;){ print pop(@pronouns_endings($i))." ".$verb-3.shift(@pronouns_endings(i+5))."\n"; }