Re: Check multiple array elements for a single condition

[TheDamian]

You could also use the Smart::Match module with smartmatching:

use Smart::Match 'all';

if ( 0 ~~ all(@array[0,1]) ) {
    say 'matched';
}

Or you could do exactly the same thing "natively", in Perl 6:

if @array[0 & 1] == 0 {
    say 'matched';
}

Damian

[Linicks]

Just thinking - what about:

if (!(@array[0]+@array[1]))

Nick

[afoken]

if (!(@array[0]]+@array[1]))

False positive if $array[0] == -$array[1].

Alexander

[Linicks]

Please explain what you mean by 'false positive'?

Thanks, Nick

[RonW]

Try if (!(@array[0] | @array[1])) instead. (For reasons afoken stated.)

[afoken]

Try if (!(@array[0] | @array[1])) instead

Don't, for the reason Marshall++ explained. Micro-optimising code to avoid typing a few characters does not improve performance, and makes maintenance a nightmare (if overused).

Also, your code assumes integers, right? I would have to look up the binary representation(s) of a float 0.0 to see if all bits are 0 there. If not, this probably won't work, resulting once again in wrong results (false negatives, in this case). Maybe floats depend on the CPU and / or math emulation library used, so the result would also depend on the machine it is running on. No, thanks. I prefer code that does not make me think about such issues.

For two or three elements, explicitly compare the elements. For more, see my generalised posting.

Playing golf is a completely different story, but then, the array's name would not be five letters long.

Alexander

[Anonymous Monk]

Isn't Smart Match deprecated?