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in reply to Re^3: following if condition fails to print its variable using perl?
in thread following if condition fails to print its variable using perl?

Here,
i had print as like print 'name :$name', ((exists $name_map->{$name} ) + ? "is in hash" : "is not in hash"), "\n"; above the if condition but it prints not in hash .without taking hash +how it can rename the contents
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Re^5: following if condition fails to print its variable using perl?
by marto (Archbishop) on Mar 15, 2017 at 10:10 UTC