Re^2: Parser Performance Question


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Re^2: Parser Performance Question

by choroba (Cardinal)

on Oct 05, 2017 at 11:57 UTC ( [id://1200727]=note: print w/replies, xml )

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in reply to Re: Parser Performance Question
in thread Parser Performance Question

Please, stop talking in riddles. Do you mean "a\\"b"?

($q=q:Sq=~/;[c](.)(.)/;chr(-||-|5+lengthSq)`"S|oS2"`map{chr |+ord
}map{substrSq`S_+|`|}3E|-|`7**2-3:)=~y+S|`+$1,++print+eval$q,q,a,
[download]

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Re^3: Parser Performance Question (updated) by LanX (Saint) on Oct 05, 2017 at 13:48 UTC
> Please, stop talking in riddles. Riddles are an efficient instrument for motivation in didactics. =) For instance a friend of mine spends loads of time in hacker competitions... ;-) > Do you mean "a\\"b"? What do you think? xD Cheers Rolf _{(addicted to the Perl Programming Language and ☆☆☆☆ :) Je suis Charlie!} update <Reveal this spoiler or all in this thread>	[reply] [d/l]
Re^4: Parser Performance Question (updated) by Eily (Monsignor) on Oct 06, 2017 at 01:44 UTC
The last two are still incorrect, as q< \\" > will be parsed as an escaped quote. `/" (?: [^"\\] \| \\. )* "/sx` is the bestest solution :-P Edit: except when I'm an idiot and confuse (?= for (?:	[reply] [d/l]
Re^5: Parser Performance Question (updated) by LanX (Saint) on Oct 06, 2017 at 02:08 UTC
> `q< \\" >` will be parsed as an escaped quote I don't understand, it IS an escaped quote and it works for me: `DB<175> $re = qr/ " (?: \\\\ \| \\" \| [^"] )* " /x; DB<176> p $a= q<x "..\\".." x> x "..\".." x DB<177> $a =~ /$re/; print $& "..\".."` [download] update maybe you should show us how you'd escape a double-quote. Cheers Rolf _{(addicted to the Perl Programming Language and ☆☆☆☆ :) Je suis Charlie!}	[reply] [d/l] [select]
Re^6: Parser Performance Question (updated) by Eily (Monsignor) on Oct 06, 2017 at 08:02 UTC
Re^7: Parser Performance Question (updated) by LanX (Saint) on Oct 06, 2017 at 08:37 UTC
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