Re: regex for strings with escaped quotes

[haukex]

use Regexp::Common qw/delimited/;

my $str = q{ x "foo \"bar\"" y };
$str =~ /($RE{delimited}{-delim=>'"'})/;
print $1, "\n";

print $RE{delimited}{-delim=>'"'}, "\n";

__END__

"foo \"bar\""
(?:(?|(?:\")(?:[^\\\"]*(?:\\.[^\\\"]*)*)(?:\")))

[morgon]

It somehow stops working when I use the regex directly and I cannot see why:

my $str = q{ x "foo \"bar\"" y };
$str =~ /(?:(?|(?:\")(?:[^\\\"]*(?:\\.[^\\\"]*)*)(?:\")))/;
print $1, "\n";

# prints nothing

[haukex]

$str =~ /(?:(?|(?:\")(?:[^\\\"]*(?:\\.[^\\\"]*)*)(?:\")))/;

It's missing the capture group that I added: /($RE{delimited}{-delim=>'"'})/

[morgon]

I don't quite understand...

I do basically this:

use Regexp::Common qw/delimited/;

print $RE{delimited}{-delim=>'"'};

And take what is printed.

How can I get to a pure regex that works then?

[morgon]

thanks, but I forgot to mention one detail:

I do not need this for a perl-program but for a perl5-compatible regex engine in Go.

I there a way to print the regex that is used?

[haukex]

I there a way to print the regex that is used?

That's what the second line of output above is. Simplification of that regex is left as an exercise to the reader :-) (Update: Nevermind.)

BTW, you can also use the -keep feature to get only the part between the quotes:

use Regexp::Common qw/delimited/;
q{ x "foo \"bar\"" y } =~ /$RE{delimited}{-delim=>'"'}{-keep}/;
print $3, "\n";  # prints: foo \"bar\"

[morgon]

Many thanks.

This is exactly what I need - let's see if I can feed that to the go-engine...