Re^5: regex for strings with escaped quotes

[haukex]

The regex is:

(?:(?|(?:\")(?:[^\\\"]*(?:\\.[^\\\"]*)*)(?:\")))

which contains no capturing groups, hence $1 isn't populated. In my first bit of code, in the regex I added an extra set of parentheses, /($RE{delimited}{-delim=>'"'})/, so there is a capturing group there. That's the equivalent of:

((?:(?|(?:\")(?:[^\\\"]*(?:\\.[^\\\"]*)*)(?:\"))))

Alternatively, you can take the first regex above and just change the non-capturing group (?:...) that surrounds the entire expression into a capturing group:

((?|(?:\")(?:[^\\\"]*(?:\\.[^\\\"]*)*)(?:\")))

Or, since you said you wanted to capture the stuff between the quotes, change that non-capturing group into a capturing one:

(?:(?|(?:\")([^\\\"]*(?:\\.[^\\\"]*)*)(?:\")))

Plus, there's a bunch of simplifications that could be made to the first regex above anyway (really just removing unnecessary groups):

/ \" [^\\\"]* (?: \\. [^\\\"]* )* \" /x

and just add capturing groups to that as needed.

[morgon]

Ahh - I did not pay attention that you introducded a new capturing group by puttting the regex into an extra pair of brackets.

Now it all makes sense - many thanks.

I've never used Regexp::Common before but it seems to contain useful stuff - I see a bright future for it in my Go-Programs :-)