Re^5: Getting for() to accept a tied array in one statement

[Veltro]

Yes, my point is that you simply can't assume an object can be de-referenced to an array. The tie mechanism useful for creating algorithms that can handle objects without implying knowledge about their implementation. Otherwise this would defeat the whole purpose using tie. So it is still a good question, any other solutions appreciated.

[hdb]

But that statement refers to the reference returned by tie which is not an array reference. The tied array works like a normal array.

[Veltro]

I don't understand, what you call 'not an array reference' is what I call 'object', so don't we mean the same thing?

In:

use ar ;
my @ar ;
my $art = tie @ar, "ar" ;
@ar = (1, 2) ;

My point is, I cannot know what $art is, so to me this is a big no no:

   my @ar-deref = @{$art};

[hdb]

Agree. But the following is perfectly ok IMHO

for(@ar) {
  print "$_\n";
}

[haukex]

My point is, I cannot know what $art is, so to me this is a big no no: my @ar-deref = @{$art};

Yes, I agree that is bad (unless $art overloads @{}), but in the code you showed here, for (tie @ary, "My::Class"), there is no such "bad" de-reference of the return value of tie happening, not even an implicit one. for (tie @ary, "My::Class") { print "$x\n" } will just print something like My::Class=HASH(0x...) - as perlancar said, it's just looping over a one-element list, the return value of tie, and not the elements of @{$art}, as you seemed to be worried about.