http://www.perlmonks.org?node_id=147802

Ok not at all good but (in my eyes at least) funny.
#!/usr/bin/perl -w use strict; open(F,$0);$_=<F>;chomp;$_.=<F>; s;^.*?\/(..).*?i(.).(.*?)\s.*?\ss(.)(.).(.).*; J$1$4 a$2o$4he$5 $3 ha$6ke$5!;; print;
See if you can guess what the c stands for in cjaph.

Darkling.
Think.

Replies are listed 'Best First'.
Re: cjaph - SOLUTION
by domm (Chaplain) on Mar 04, 2002 at 20:20 UTC
    You open the script itself (location stored in $0) on filehandle F and assign the first two lines to $_.

    Then you start a substitution operating on $_, with ; as a delimiter, so de-obfuscated (using a | as delimiter) it looks like:

    $_=~s|^.*?\/(..).*?i(.).(.*?)\s.*?\ss(.)(.).(.).*|J$1$4 a$2o$4he$5 $3 +ha$6ke$5!|;
    You basically scan the first two lines for some stuff:
    1. The two chars following the first slash go into $1 ('us')
      #!/usr/bin/perl -w
      use strict;
      
    2. Then you scan for the next 'i' and save the following char in $2 ('n')
      #!/usr/bin/perl -w
      use strict;
      
    3. You skip the next char and save everything up to the next space in $3 ('perl')
      #!/usr/bin/perl -w
      use strict;
      
    4. You skip to the next space followed by 's' and save the next char in $4 ('t')
      #!/usr/bin/perl -w
      use strict;
      
    5. The next char goes into $5 ('r')
      #!/usr/bin/perl -w
      use strict;
      
    6. Then skip one and save the last in $6 ('c')
      #!/usr/bin/perl -w
      use strict;
      
    and then print the new value of $_.

    But I still don't know what the c in cjaph stands for ...

      Ok. Just to stop everyone from guessing (because I know you've all been worrying about it for days now!) the "c" in cjaph, as is quite obvious from the nature of the japh, stands for "crap".

      Darkling.
      Think.