Re: Perl rounder...

[maverick]

Sorry dude, it's already been done.

printf("%.$ARGV[1]f\n",$ARGV[0]);

printf takes a sting that describes what you want to print. In your case a floating point number (f) with a precision that you specify as the second arg ($ARGV[1]) using the value in $ARGV[0]

/\/\averick
OmG! They killed tilly! You *bleep*!!

[abaxaba]

Explains the negative comments votes.... REAP it then.