|Problems? Is your data what you think it is?|
Re: Re: Rolling a biased dieby ferrency (Deacon)
|on Apr 12, 2002 at 13:39 UTC||Need Help??|
Update:I'm totally wrong! Please ignore me! And take my advice: try the code before you claim it's broken :) Sorry, IO.
I don't think you want to put the rand() inside the loop. I think to get the correct results, you need to choose one random number outside the loop, and test it vs. the sum as you go along.
Try out a simple case by hand:
Assuming your first iteration picks up (1 => 1), you have:
What you really want is something like this:
I'm sure there's a golfier way to do it, but this demonstrates the basic idea.
Update: Okay, after actually trying the code, I believe I'm totally wrong. I think that what I thought was a combination of two bugs may actually be a clever solution. Though I'm still not sure I believe it produces the correct result distribution. IO, would you care to describe how it works? Sorry about that.