Re: Re: RegEx Challenge

[Adam]

The look-behind. It looks at the original scalar rather then the modified. It makes sense, but it could really go either way.

[japhy]

Ah yes, that. I've witnessed people getting bitten by that.

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Jeff[japhy]Pinyan: Perl, regex, and perl hacker, who'd like a (from-home) job
s++=END;++y(;-P)}y js++=;shajsj<++y(p-q)}?print:??;