Re^2: Schwartzian Transform and memory allocation.

[Aristotle]

Why split once for the Schwartzian Transform then again for the output?

open FILE, "<$data_file";
my @file_data =
    sort { $a->[$variable-1] cmp $b->[$variable-1] },
    map [ split(/\|/) ],
    <FILE>;
close FILE;

print qq(<TABLE BORDER="1">);
for my $row (@file_data){
    print ( qq(<TR>), map(qq(<TD>$_</TD>), @$row), qq(</TR>) );
}
print qq(</TABLE>);

____________
Makeshifts last the longest.

[flounder99]

I think the

sort { $a->[$variable-1] cmp $b->[$variable-1] },

line should be

sort { $a->[$variable] cmp $b->[$variable] },

The -1 was added by abigail to skip over the $_ that was tacked on at the beginning of the anon array. You're no longer doing that.

--

flounder

[Aristotle]

No, actually, Abigail added the -1 because there was no longer an extra element to skip over. It doesn't make sense to subtract 1 to skip over an extra element, does it? The same premise holds true in my snippet as well.

Makeshifts last the longest.