Re: Re: Serializing coderefs

[jmerelo]

Looks like this does the job:

my $s = sub { my $k = shift; return $k;};
use B::Deparse;
my $deparse = B::Deparse->new("-p", "-sC");
print  $deparse->coderef2text($s);

The morale here: when in doubt, ask, but don't wait for the answer, work on it...

[Aristotle]

I don't want to be adverse, but between your last post and the first one lie barely 30 minutes. The intermediate post makes it seem even more fidgety. I hope it's not the norm for you to ask questions you can answer for yourself within half an hour - an occasional occurence is very forgivable as even the best of us get stuck in boneheaded mode sometimes, but we are all expected to try and avoid false impatience.

Makeshifts last the longest.

[Anonymous Monk]

Well, I can just say what I said in my previous post: when in doubt, ask, but don't wait for the answer, work on it... Would you consider me any smarter if I hadn't answered my own question?

[Aristotle]

The question is not about smarts, it's about patience.

Makeshifts last the longest.

[ignatz]

There's something about struggling with a problem for hours and then giving up and asking others for help that seems to jar stuff loose in the brain. It happens to me all the time. Maybe it's related to what Poe called the Imp of the Perverse.

()-()
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[merlyn]

That of course "does the job" for a limited subset of coderefs, since at the moment there's no way to know the closure bindings (or get at them for their current values), so it'll come back to life pointing at an entirely wrong set of closure-bound variables.

This is a known issue, and being considered during the development of the Perl6 runtime engine.

-- Randal L. Schwartz, Perl hacker

[jmerelo]

Is there a better way? Any reference to the cases where it will fail?

[merlyn]

It will fail on this:

my $increment_by_secret = do {
  my $secret_number = 7;
  sub { $secret_number + shift };
};

It fails because there's no access to $secret_number from outside the coderef, so we can't tell what the "magic constant" should be. All you get is:

{
    ($secret_number + shift(@_));
}

(Just tested.)

-- Randal L. Schwartz, Perl hacker