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RE: Re: searching backwards in a string

by Anonymous Monk
on Jun 13, 2000 at 16:06 UTC ( #17875=note: print w/replies, xml ) Need Help??


in reply to Re: searching backwards in a string
in thread searching backwards in a string

>> while($text =~ /(.{0,80})\s+/g) { # result in $1 } << I believe that the above snippet is an infinite loop. However, if TEXT is a filehandle then while(<TEXT> =~ /(.{0,80})\s+/g){ # result in $1 } should kill all trailing space and line returns. Isn't that what chomp is for, though?
  • Comment on RE: Re: searching backwards in a string

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RE: RE: Re: searching backwards in a string
by nuance (Hermit) on Jun 13, 2000 at 16:49 UTC

    If all your code did was that very small snippet then it would indeed be an infinite loop. However, the loop was given as an example and the comment was supposed to be replaced with code that does something useful

    the inside of the loop should look something like: (untested)

    push @lines, substr $_, 0, length $1, "";

    Nuance

RE: RE: Re: searching backwards in a string
by plaid (Chaplain) on Jun 14, 2000 at 20:58 UTC
    The code snippit does not loop infinitely, regardless of loop body. As stated, the result is in $1. It then becomes trivial to write a test program to see how it works. In fact, I'll take care of it for you.
    use strict; my $text = "This is a long line that I am typing to demonstrate". " the way that my regular expression works and it's a". " run-on sentence too but I don't really care."; print $1, "\n" while($text =~ /(.{0,20})\s+/g);
    Has a slight problem of not grabbing the last line, but it's 99% of the way there, and besides, that's why you should use a module in the first place:)

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