Re: A better mod (%) operator?

[rinceWind]

If you take a look at Math::BigInt, you will find that the method bdiv in list context returns quotient and remainder.

SYNOPSIS
  use Math::BigInt;
  $i = Math::BigInt->new($string);
  $i->bneg return BINT               negation
  $i->babs return BINT               absolute value
  $i->bcmp(BINT) return CODE         compare numbers (undef,<0,=0,>0)
  $i->badd(BINT) return BINT         addition
  $i->bsub(BINT) return BINT         subtraction
  $i->bmul(BINT) return BINT         multiplication
  $i->bdiv(BINT) return (BINT,BINT)  division (quo,rem) just quo if sc
+alar
  $i->bmod(BINT) return BINT         modulus
  $i->bgcd(BINT) return BINT         greatest common divisor
  $i->bnorm return BINT              normalization
  $i->blsft(BINT) return BINT        left shift
  $i->brsft(BINT) return (BINT,BINT) right shift (quo,rem) just quo if
+ scalar
  $i->band(BINT) return BINT         bit-wise and
  $i->bior(BINT) return BINT         bit-wise inclusive or
  $i->bxor(BINT) return BINT         bit-wise exclusive or
  $i->bnot return BINT               bit-wise not

Although it's a bit slow and clunky, Math::BigInt's overload mechanism makes a good attempt at a drop-in replacement for n bit integers.