Re: Re: Re: Re: Re: checking the end of line

[dimmesdale]

$1 captures 12, you are right. However, you do an array slice thing with the [0] part -- which on my machine perl 5.6.1 AS build 633 produces an error; I have to move the parentheses around the regex itself. And when you print it, it shows a 1 on my computer. I just don't see the need for the [0]

[I0]

What error does it produce on your machine? On mine, the array slice is necessary to put the regex in list context so that it returns the captured string instead of the true or false value it returns in scalar context

[dimmesdale]

Syntax error becuase of )[

With the parens around JUST the regex it works (but returns a 1).

Assigning the results to an array or using the $1 variable, however, would get around this if the user is having any problems ...

Has anyone else been having problems with PM? I checked my firewall, and it seems that the banners up top keep 'timing-out', so the whole page takes forever to load.

[I0]

If you're getting a syntax error, perhaps you typed it in wrong.

Perhaps you meant

if($path =~ /(\d+)$/ == 0) {
    print "No number found\n";
} else {
    print "number is $1\n"; 
}