Re: Help with Numbers..Please

[perlguy]

Update: Abigail-II's point is well taken on posting incorrect code. Strike this one and don't bother. I found the problem case after I had already posted. Appologies.

Update 2: This following regex should work better, and won't fail in the test cases. The same number of digits will be in the output, unless all 9s are in the string, in which case it will just add 1 digit to the front of the string to accomodate. Again, just an exercise.

$number =~ s/([^9]?9*)$/$1+1/e;

Back to the original post:

Here is a regular expression way to do it:

my $number = '0001999';
$number =~ s/([^9]9+|\d)$/$1+1/e;
print "$number\n";

It has a flaw: if all the numbers are 9, it will drop the last nine and add a 10, so probably not something you would want to use in production code. But the other test cases that I worked with were fine. It was more of an exercise than anything.

[Abigail-II]

Uhm, if you already know it's flawed, by bother posting? How useful is incorrect code?

Anyway, here's a regexp solution that is much simpler, and doesn't fail on "9":

    s/(\d+)/$1+1/e;

Abigail

[perlguy]

It won't fail on '9', but your proposed alternative regular expression won't work on '009' for example, as '10' would be the output instead of the requested '010'. Just an observation.