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Re: Using an array in a hashby young perlhopper (Scribe) |
on Aug 08, 2000 at 04:05 UTC ( [id://26703]=note: print w/replies, xml ) | Need Help?? |
Instead of directly answering your question (which other people
have already done, well) I'll give you a few quick pointers
on perl references (which other people will probably also do).
First, you might want to take a look at perlref, (i.e. type
perldoc perlref), it contains a pretty good explanation of
how to use references in perl. Basically, references are scalars, if you have a C background, just think of them as pointers, the only difference being that you can't do pointer arithmetic on them. (i.e. no $myref++; or similar). Also, since perl is not a strongly typed language, you are responsible for keeping track of what data type a reference points to. There's no such thing as an 'array reference' or a 'hash reference', just a reference, which can point to either an array or a hash. Some examples of referencing and dereferencing
The difference between a 'real' array and an anonymous one is that when you modify the array referenced by $reftoactualarray, the contents of @array actually change. If you change the array referenced by $reftoanonymousarray, nobody else will see the changes you made. Dereferencing arrays of hashes or hashes of arrays, or any complex data structure like that, can get pretty hairy.
Good Luck, Corrections welcome.
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