in reply to Re: Re: Re: Re: Re: Alpha base-26 to base-10... (golf)
in thread Alpha base-26 to base-10...

Ah, that's lc the lower-case function, not 1c the hex representation of 28.

But I still don't understand why you can have the following pop without a delimiter after the assignment statement. I think the purpose of the pop is to subtract one from the result.

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RE(7): Alpha base-26 to base-10... (golf)
by Tomte (Priest) on Jul 01, 2003 at 18:17 UTC

    I may be mistaken, but I read it the way, that the pop delivers the scalar parameter for lc, (replace it with shift, the result is the same).

    the basic is that you get a list of all values between a and the parameter, evaluated in scalar-context (I had this wrong at first :-), you get the length of the list, which is of course the decimal representation.


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