Re: 'and next' question

[hanenkamp]

Try

++$hash{$_} and next if $_ > 5;

Update: Thanks Anonymous Monk. You're right, I was wrong. Please ignore the rest of this...it doesn't hold water.

Be careful though about using and this way. Since the precedence of and is extremely low, this is the same as saying:

# Increment $hash{$_} then if $_ > 5 loop next
++$hash{$_} and (next if $_ > 5);

When you might rather mean:

# If $_ > 5 then increment $hash{$_} and loop next
(++$hash{$_} and next) if $_ > 5;

It depends on when you want %hash to be changed. Often, I will avoid statements like this at the cost of brevity to avoid misunderstanding between myself and the compiler on this sort of nuance--or at least use paren's to make the situation explicit.

[Anonymous Monk]

  ++$hash{$_} and next if $_ > 5;

Be careful though about using and this way. Since the precedence of and is extremely low, this is the same as saying:

  # Increment $hash{$_} then if $_ > 5 loop next
  ++$hash{$_} and (next if $_ > 5);

No, it is not the same at all. The if is a statement modifier and will always be tested first.

  ++$hash{$_} and next if $_ > 5;

is, as one would expect, the same as:

$_ > 5 and (++$hash{$_} and next);