Re: Re: Regex to add space after punctuation sign

[dda]

Thank you, Abigail. Can you please explain how does the replacement part of your expression work? If I understand correctly, /e evaluates $1 || "$2 " -- that way if $1 is not empty, it should not add second part? P.S. I added end-of-line processings as was suggested by aragorn:

s/(\d[,.]\d)|([^\w\s](?!\s)(?!$))/$1 || "$2 "/ge;

[Abigail-II]

Evaluating $1 || "$2 " means you get $1 if $1 is true (which means, anytime \d[.,]\d matches), otherwise you get $2 (the punctation character), followed by a space.

I would handle end-of-line processing as follows:

s/(\d[,.]\d)|([^\w\s])(?=\S)/$1 || "$2 "/ge;

A single positive look-ahead is, IMO, more clear than two negative look-aheads.

Abigail

[dda]

Thank you. You are the best!