Hi all, I'm learning Perl (my only other programming experience is Tcl) and I'm having some trouble.
I'm confused over lists, so I looked up some help and
found this thread at Stack Overflow.
I looked up the perldoc of reverse (
reverse) and I on the page, there is some code, which I've slightly modified:
#!/usr/bin/perl
use strict;
use warnings;
print join(", ", reverse "world", "One"), "\n"; # One, world
print scalar reverse ("dlrow ,", "owT"),"\n"; # Two, world
$_ = "dlrow ,eerhT";
print reverse; # No output, list context
$_ = "dlrow ,ruoF";
print scalar reverse; # Four, world
I get the following output:
One, world
Two, world
Four, world
My first question is why isn't the third line printed? Reverse supposedly returns a list and the perldoc of print says that a list is one of it's arguments. Why doesn't this work?
My second question is that if I explicitly state the
$_ after reverse in the third print statement, then it prints out the string, but it is NOT reversed:
#!/usr/bin/perl
use strict;
use warnings;
print join(", ", reverse "world", "One"), "\n"; # One, world
print scalar reverse ("dlrow ,", "owT"),"\n"; # Two, world
$_ = "dlrow ,eerhT";
print reverse $_; # No output, list context
$_ = "dlrow ,ruoF";
print scalar reverse $_; # Four, world
I get the following output:
One, world
Two, world
dlrow, eerhTFour, world
What is going on here? Why does listing $_ explicitly as an argument to reverse cause print to work, but reverse() is not performed?
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