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Hi all, I'm learning Perl (my only other programming experience is Tcl) and I'm having some trouble. I'm confused over lists, so I looked up some help and found this thread at Stack Overflow. I looked up the perldoc of reverse (reverse) and I on the page, there is some code, which I've slightly modified:
#!/usr/bin/perl use strict; use warnings; print join(", ", reverse "world", "One"), "\n"; # One, world print scalar reverse ("dlrow ,", "owT"),"\n"; # Two, world $_ = "dlrow ,eerhT"; print reverse; # No output, list context $_ = "dlrow ,ruoF"; print scalar reverse; # Four, world
I get the following output:
One, world Two, world Four, world
My first question is why isn't the third line printed? Reverse supposedly returns a list and the perldoc of print says that a list is one of it's arguments. Why doesn't this work? My second question is that if I explicitly state the $_ after reverse in the third print statement, then it prints out the string, but it is NOT reversed:
#!/usr/bin/perl use strict; use warnings; print join(", ", reverse "world", "One"), "\n"; # One, world print scalar reverse ("dlrow ,", "owT"),"\n"; # Two, world $_ = "dlrow ,eerhT"; print reverse $_; # No output, list context $_ = "dlrow ,ruoF"; print scalar reverse $_; # Four, world
I get the following output:
One, world Two, world dlrow, eerhTFour, world
What is going on here? Why does listing $_ explicitly as an argument to reverse cause print to work, but reverse() is not performed?

In reply to New user, confusion over print and lists by jktstance

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