This one-liner (versus answers with hashes and inspired by another answer) is working for me but has not been very rigorously tested (as run on AS Perl 5.16.3):
@foo = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10);
@bar = (0, 1, 2, 5, 7, 9, 11, 12, 13, 14);
my @diff = grep {my $baz = $_; ! grep($_ == $baz, @bar)} @foo;
print join(",", @diff);
Gives:
3,4,6,8,10
Switch the lists around in the nested greps to go from being "in foo but not also bar" to "in bar but not also foo".
-Simon
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