You can get the same behaviour for a named variable if you declare it outside the loop:
my $line;
while ($line = <>) {
...
With the declaration inside the condition, it's in fact a different variable every time, so Perl needs to create an extra scope for it, as B::Deparse shows you: $ perl -MO=Deparse -e 'while (<>) { /(.)/ }'
while (defined($_ = readline ARGV)) {
/(.)/;
}
-e syntax OK
$ perl -MO=Deparse -e 'while (my $line = <>) { $line =~ /(.)/ }'
while (defined(my $line = readline ARGV)) {
do {
$line =~ /(.)/
};
}
-e syntax OK
Also note that lines containing 0 as their first or second word are not printed.
map{substr$_->[0],$_->[1]||0,1}[\*||{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^*ARGV,3]
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