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GrandFather's solution may be shorten if a short one-liner is what you're after.

# reisinge perl -E 'say [ sort { $ARGV[$b] <=> $ARGV[$a] } 0..$#ARGV ]->[0]' 42 1 +000 999 0 -1 # GrandFather perl -E '$m=0; $ARGV[$m] > $ARGV[$_] or $m=$_ for 1..$#ARGV; say $m' 4 +2 1000 999 0 -1 # Shorten, similar performance perl -E '$i=0; ($ARGV[$m] > $_ or $m=$i), $i++ for @ARGV; say $m' 42 1 +000 999 0 -1

Below, please find a benchmark script for testing against a large list.

use strict; use warnings; use List::Util 'shuffle'; use Time::HiRes 'time'; # Return index to biggest element. sub reisinge { [ sort { $_[$b] <=> $_[$a] } 0 .. $#_ ]->[0]; } sub GrandFather { my $idxMax = 0; $_[$idxMax] > $_[$_] or $idxMax = $_ for 1 .. $#_; $idxMax; } sub biggest_elm { my ($idxMax,$idx) = (0,0); ($_[$idxMax] > $_ or $idxMax = $idx), $idx++ for @_; $idxMax; } srand 0; my @list = shuffle 1..4e5; for my $code (qw( reisinge GrandFather biggest_elm )) { no strict 'refs'; my ($start, $idx) = (time, $code->(@list)); printf "Index %d, Seconds (%-11s): %0.03f\n", $idx, $code, time - $start; }

Regards, Mario.

Edit: Added benchmark script.


In reply to Re^2: How can I find the index of the biggest element in an array? by marioroy
in thread How can I find the index of the biggest element in an array? by Anonymous Monk

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