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GrandFather's solution may be shorten if a short one-liner is what you're after.

```# reisinge
perl -E 'say [ sort { \$ARGV[\$b] <=> \$ARGV[\$a] } 0..\$#ARGV ]->[0]' 42 1
+000 999 0 -1

# GrandFather
perl -E '\$m=0; \$ARGV[\$m] > \$ARGV[\$_] or \$m=\$_ for 1..\$#ARGV; say \$m' 4
+2 1000 999 0 -1

# Shorten, similar performance
perl -E '\$i=0; (\$ARGV[\$m] > \$_ or \$m=\$i), \$i++ for @ARGV; say \$m' 42 1
+000 999 0 -1

Below, please find a benchmark script for testing against a large list.

```use strict;
use warnings;
use List::Util 'shuffle';
use Time::HiRes 'time';

# Return index to biggest element.

sub reisinge {
[ sort { \$_[\$b] <=> \$_[\$a] } 0 .. \$#_ ]->[0];
}

sub GrandFather {
my \$idxMax = 0;
\$_[\$idxMax] > \$_[\$_] or \$idxMax = \$_ for 1 .. \$#_;
\$idxMax;
}

sub biggest_elm {
my (\$idxMax,\$idx) = (0,0);
(\$_[\$idxMax] > \$_ or \$idxMax = \$idx), \$idx++ for @_;
\$idxMax;
}

srand 0;

my @list = shuffle 1..4e5;

for my \$code (qw( reisinge GrandFather biggest_elm )) {
no strict 'refs';
my (\$start, \$idx) = (time, \$code->(@list));

printf "Index %d, Seconds (%-11s): %0.03f\n",
\$idx, \$code, time - \$start;
}

Regards, Mario.

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