comment on

testing if my approach also works here ...

The difference is that you have positive clauses like The programmer likes cherries , which result in 12 zeroes instead of only 3:

6 for (programmer)x(apples,pears)
6 for (blacksmith,fisherman) x (cherries)

That's why you fewer clauses than the OP to be decisive.

Applying all clauses:

FRUITS     PROFESSIONS  NAMES

              P B F   
cherries      . 0 0
apples       0 0 .      John
pears       0 0 0 

cherries      0 0 0
apples       0 . 0      Patrick
pears       0 . 0 

cherries      . 0 0
apples       0 0 0      Edward
pears       0 0 0
[download]

=> (Edward,programmer,cherries)
=> (fisherman,John, apples)
excluding other possibilities

FRUITS     PROFESSIONS  NAMES

              P B F   
cherries      0 0 0
apples       0 0 1      John
pears       0 0 0 

cherries      0 0 0
apples       0 0 0      Patrick
pears       0 . 0 

cherries      1 0 0
apples       0 0 0      Edward
pears       0 0 0
[download]

=> (Patrick, blacksmith, pears)

I'd say a bit too easy. :)

But I think it's obvious now how we could use this "hyper-cube" solver for creating riddles in low dimensions.

update

Though I'm not sure if a "solvable" riddle (i.e. only one solution possible) is always as obvious as the examples given so far.

For instance what if every cut has at least 2 undefined points, such that the first step is not obvious.

Cheers Rolf
_{(addicted to the Perl Programming Language and ☆☆☆☆ :)

Wikisyntax for the Monastery}

update

This riddle is even easier and already solved right away without eliminations. since there is only one possibility for pears after initially filling the matrix.

In reply to Re^2: My first cpan module - App::ForKids::LogicalPuzzleGenerator by LanX
in thread My first cpan module - App::ForKids::LogicalPuzzleGenerator by pawel.biernacki

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