How do I do this in one line?

sub build_list {
    ($RECORD,$RI,$RECORDxRI,$RECORDxRI_count_REF,$EACH_RECORD_REF) = @
+_;

    %RECORDxRI_count = %$RECORDxRI_count_REF;
    %EACH_RECORD     = %$EACH_RECORD_REF;

    $RECORDxRI_count{$RECORDxRI}++;
    $EACH_RECORD{$RECORD} = '';
    return(\%RECORDxRI_count,\%EACH_RECORD);
}

while <DATA> {

    @record = split('\t',$_);
    $RI = @record[38];

    ($RECORD,$junk) = split('{',@record[54]);
    $RECORDxRI = $RECORD . ',' . $RI; 

    ($RECORDxRI_count_REF,$EACH_RECORD_REF) = &build_list($RECORD,$RI,
+$RECORDxRI,\%$RECORDxRI_count,\%EACH_RECORD);
    %RECORDxRI_count = %RECORDxRI_count_REF;
    %EACH_RECORD = %$EACH_RECORD_REF;

        # NOTE: I have to dereference both hashes
        # on every iteration of the while loop
} # end while data
[download]

OK ... I understand that ONE line is a little overzealous, but I'm actually interested in making the function call to &build_list in one line...

Is there a way to get a full hash without dereferencing the hashes I pass to the routine on every iteration of this loop?

Could I get

&build_list(\%hash1,\%hash2);
[download]

to create that hash on its first pass and on subsequent iterations of "while" use the same hash?

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