117 116 117. But with caveats.
The main caveat is that I can add or lose characters depending on exact behaviour of these additional functions. (Particularly important is the behaviour of "a". I assumed that it returned 0,1 and added returns on prints but not a ?.) Here are the exact functions as I used them for my solution:
sub a {
print @_, "\n";
my $r = <STDIN>;
if ($r =~ /y/i) {
return 1;
}
elsif ($r =~ /n/i) {
return 0;
}
else {
print "Sorry, I don't understand that. Please answer Y/N.\n";
a(@_);
}
}
sub t {
print "What is your animal?\n";
my $ans = <STDIN>;
chomp($ans);
return $ans;
}
sub i {
my ($guessed, $user_answer) = @_;
chomp($guessed, $user_answer);
print "Please enter a question that would be true for a "
. "$user_answer, but false for a $guessed:\n";
my $ans = <STDIN>;
chomp($ans);
return $ans;
}
sub w {
if (a("\nDo you want to continue?")) {
print "\nStarting a new game.\n";
}
else {
print "BYE!\n";
exit();
}
}
Add to that my one free initialization:
$Q{a}="golfer";
And then my solution:
# 1 2 3 4 5 6
+7 8 9 10 11
#123456789_123456789_123456789_123456789_123456789_123456789_123456789
+_123456789_123456789_123456789_123456789_1234567
{*q=\%Q;*q=$q{a$q{q}}while$q{q};$q{0}{a}=$q{a},$q{1}{a}=t,$q{q}=i($q{a
+},$q{1}{a})if!a"Is your animal a $q{a}?";w,redo}
# Was
#{*q=*Q;*q=$q{a$q{q}}while$q{q};$q{0}{a}=$q{a},$q{1}{a}=t,$q{q}=i($q{a
+},$q{1}{a})if!a"Is your animal a $q{a}?";w&&redo}
UPDATE
jarich is right, I forgot to test something. My first
typeglob assignment was wrong
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