Hi,
(Now I call *this* node archaeology)
this is for german, very dumb. But a nice recursive
aproach, suitable for numbers up to 999 999 999 with
nice german grammar. Easily extendable.
sub de_number {
my $positive = shift;
my $out;
my @tokens1 = qw(null ein zwei drei vier fünf sechs sieben acht ne
+un zehn elf zwölf);
my @tokens2 = qw(zwanzig dreissig vierzig fünfzig sechzig siebzig
+achtzig neunzig hundert);
# my @tokens3 = qw(million milliarde billion billiarde); # Not need
+ed now
if($positive >= 0 && $positive <= 12) {
$out = $tokens1[$positive];
} elsif($positive >= 13 && $positive <= 19) {
$out = $tokens1[$positive-10].'zehn';
} elsif($positive >= 20 && $positive <= 100) {
my $one_idx = int $positive/10-2;
my $ten_idx = $positive-($one_idx+2)*10;
$out = $tokens1[$ten_idx].'und' if $ten_idx;
$out .= $tokens2[$one_idx];
} elsif($positive >= 101 && $positive <= 999) {
my $one_idx = int $positive/100;
$out = $tokens1[$one_idx].'hundert'.&de_number($positive-$one_idx*
+100);
} elsif($positive >= 1000 && $positive <= 999999) {
my $one_idx = int $positive/1000;
my $tausend = $positive-$one_idx*1000;
my $nonull = $tausend ? &de_number($tausend) : '';
$out = &de_number($one_idx).'tausend'.$nonull;
} elsif($positive >= 1000000 && $positive <= 999999999) {
my $one_idx = int $positive/1000000;
my $mio = $positive-$one_idx*1000000;
my $nonull = $mio ? ' '.&de_number($mio) : '';
my $one = $one_idx == 1 ? 'e' : '';
$out = &de_number($one_idx).$one.' million';
$out .= 'en' if $one_idx > 1;
$out .= $nonull;
}
return $out;
}
Bye
PetaMem
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