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:) Ok, now that I better understand what you're asking, here's my regex solution. I think that this improves upon some other methods by starting with the longest and working down to the shortest, (quitting as soon as a match is found).

use strict; use warnings; my @array = ( "this is a string is", "a string this is", "tie a string together" ); my $string = join "|", @array; my $repeat = '\|.*?\1.*?' x ( scalar(@array) - 1 ); for my $n ( reverse ( 1 .. length( $string ) ) ) { next unless $string =~ /(.{$n}).*?$repeat/; print $1, "\n"; last; }

Ob-Update: This assumes the substrings don't overlap. And I've tinkered with the code to make it keep track of what the original substrings looked like. In so doing, I used the | character as a delimiter, which means it shouldn't appear in the original substrings. Thanks danger for the polite nudge. ;)


Dave


"If I had my life to live over again, I'd be a plumber." -- Albert Einstein

In reply to Re: Re: Re: finding longest common substring by davido
in thread finding longest common substring by revdiablo

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