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Nice problem! and some nice solutions ... everyone loves a diversion ...

Here's mine. For variety, and cos I'm looking for a new job (wink) I went for an OO approach. Certainly not the least characters, and I'm not sure it adds much in readability, but something different. Perhaps not even that, as I suspect that it is really a dressed up version of the iterative solution that was given already. Anyhow, here it is. I had fun doing it.

The object itself:

package SpiralSq; use strict; sub new { my ($class, $size, $offset) = @_; $offset = 1 unless defined ($offset); my $self = { 'size'=>$size, 'offset' => $offset, 'nextoffset' => (4*($size - 1) + $offset)}; bless $self, $class; return $self; } sub getInside { my ($self) = @_; $self->{'inside'} = new SpiralSq($self->{'size'} - 2, $self->{'nextoffset'}) unless (defined $self->{'inside'}); return $self->{'inside'}; } sub getRow { my ($self, $r) = @_; my $o = $self->{'offset'}; my $s = $self->{'size'}; my $n = $self->{'nextoffset'}; my @row; if ($r == 0) { @row = ($o .. ($s - 1 + $o)); } elsif ($r == $s - 1) { @row = ((2*($s - 1) + $o) .. (3*($s - 1) + $o)); @row = reverse @row; } elsif ($r < $s) { @row = (($n - $r), $self->getInside->getRow($r - 1), ($s -1 + $r + $o)); } else { die "error!"; } return @row; } 1;

And a test script:

#!/opt/perl/bin/perl -w use strict; use SpiralSq; my $n = 18; my $s = new SpiralSq($n); for (0 .. ($n-1)) { print join " ", $s->getRow($_); print "\n"; }

In reply to Re: Spiraling integers by danmcb
in thread Spiraling integers by Elijah

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