If 2^N could become m^n, then you could use a recursive solution:
(Updated: cleaned up slightly!)
#! perl -slw
use strict;
sub expand{
return @{ $_[0] } if @_ == 1;
map{
my $x = $_;
map{ $x * $_ } &expand;
} @{ pop @_ };
}
my @mat = ( [ -1, 2 ], [ 3, -4 ] );
printf +("%s " x @mat ) . '= ', map{ "[ @$_ ] " } @mat;
print join ' ', expand( @mat );
@mat = ( [ 1, 2 ], [ 3, 4 ], [ 5, 6 ], );
printf +("%s " x @mat ) . '= ', map{ "[ @$_ ] " } @mat;
print join ' ', expand( @mat );
@mat = ( [ 1, 2, 3 ], [ 4, 5, 6 ], [ 7, 8, 9 ], );
printf +("%s " x @mat ) . '= ', map{ "[ @$_ ] " } @mat;
print join ' ', expand( @mat );
__END__
P:\test>junk
[ -1 2 ] [ 3 -4 ] = -3 6 4 -8
[ 1 2 ] [ 3 4 ] [ 5 6 ] = 15 30 20 40 18 36 24 48
[ 1 2 3 ] [ 4 5 6 ] [ 7 8 9 ] =
28 56 84 35 70 105 42 84 126 32 64 96 40 80 120 48 96 144 36 72 108 45
+ 90 135 54 108 162
Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
Lingua non convalesco, consenesco et abolesco. -- Rule 1 has a caveat! -- Who broke the cabal?
"Science is about questioning the status quo. Questioning authority".
In the absence of evidence, opinion is indistinguishable from prejudice.
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