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From perldoc perlvar: ...if a system or library call fails, it sets this variable. This means that the value of $! is meaningful only immediately after a failure As there was no failure, the value of $! is meaningless in your example.
-- <http://dave.org.uk> "The first rule of Perl club is you do not talk about
Perl club." In reply to Re: qx and $!
by davorg
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