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Hi anonymous monk, yes I'm still finding this confusing.

Well hold onto your pants :)

You mentioned it is confusing $dataset for a hashref.

Look at the @beef equivalent example, it is this line that dies with Can't use an undefined value as an ARRAY reference

my @beef = @{ $dataset->{ $col[0] } };
This line is really
my $key = $col[0] ; my $meat = $dataset->{ $key }; my @beef = @{ $meat };
I misspoke when I said it is confusing $dataset for a hashref , in actuality, $dataset is a hashref.

The problem is, $key is not in $dataset, so $meat is undef

Since meat is undef, trying to treat $meat as an array by de-referencing it, triggers a warning if you have warnings on, and triggers an error, if you have strict on.

## no warnings or errors $ perl -e "print @{ undef() }; print 6" 6 ## a warning is issued, but 6 still gets printed $ perl -we "print @{ undef() } Use of uninitialized value in array dereference at -e line 1. 6 ## with strict the warning is fatal, 6 not printed cause program died $ perl -Mstrict -we "print @{ undef() } Can't use an undefined value as an ARRAY reference at -e line 1.
See References quick reference

To avoid this error, you might add

next unless $meat;
You don't want to disable strict :)

Lets take apart a simpler example, one that builds @data

push @{$data[$nr - 1]->{shift(@cols)}},\@cols;
aka
push @{ $data[ $nr - 1 ]->{ shift(@cols) } }, \@cols;
aka
push @{ $data[ $fileCount ]->{ shift @col } }, \@col;
is really
my $Hashref = $data[ $fileCount ]; if( not $Hashref){ $Hashref = $data[ $fileCount ] = {}; } my $key = shift @col; my $Arrayref = $Hashref->{ $key }; if( not $Arrayref ){ $Arrayref = $Hashref->{ $key } = []; } push @{ $Arrayref }, \@col;
or even
my $Hashref = $data[ $fileCount ]; if( not $Hashref){ my %newHashThatIsOnlyNamedHere; $Hashref = $data[ $fileCount ] = \%newHashThatIsOnlyNamedHere; } my $key = shift @col; my $Arrayref = $Hashref->{ $key }; if( not $Arrayref ){ my @newArrayThatIsOnlyNamedHere; $Arrayref = $Hashref->{ $key } = \@newArrayThatIsOnlyNamedHere; } push @{ $Arrayref }, \@col;

In reply to Re^5: Combining 3 files by Anonymous Monk
in thread Combining 3 files by garyboyd

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