comment on

The first task is to get the "number" that you wish to track from the input lines.

The second step is simply to count using a hash table. It is not necessary to test for exists(). Perl will create a new key if the key doesn't exist.

#!/usr/bin/perl -w
use strict;

my %count;

open (INPUT, '<', "some_input_file") or
   die "unable to open some_input_file");

while (<INPUT>)
{
   my ($number) =~ /(\d+)/; #maybe????
   next unless $number; #skip undef's
   $count{$number}++; #new key if $number not there
}
foreach my $number (sort{$a <=> $b} keys %count) #numeric sort
{
    print "$number occurs $count{$number} time(s)\n";
}
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Try again and show some just a couple of lines of example input and your revised code.

There is no need to iterate over all 101 possibilities for the number on each line. Process each line once, get the number, make a decision and it is "over with" - don't loop 100 times for each input line.

In reply to Re: counting elements using a hash by Marshall
in thread counting elements using a hash by bk1388

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