Ah, so P() is 1 (the probablity of having anything happen).
Ok, you'd have to ammend my code with
return 1 if !@_:
at the top or something
Ron Steinke
rsteinke@w-link.net
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P(r1) = (r1 - r0) P()
= r1
Correct? | [reply] [d/l] |
Yes, that's correct
Or, like rsteinke explained it much better than I can in the chatterbox: "If P(r_1) is the probability of getting r_1, and P(r_1,r_2) is the probability of getting r_1 and r_2, then P() is the probability of anything at all happening (unconstrained), which is 1"
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