Because the golf isn't complete without an insanely short regex solution:
sub japhy { # 74
our$P="";pop=~m{(.+).?(??{reverse$1})
(?{length$P<length$&and$P=$&})^}xs;$P
}
Update: inspired by ccn's array approach:
sub japhy { # 68
our@P="";pop=~m{(.+).?(??{reverse$
1})(?{$P[length$&]=$&})^}xs;$P[-1]
}
_____________________________________________________
Jeff
japhy Pinyan,
P.L., P.M., P.O.D, X.S.:
Perl,
regex,
and
perl
hacker
How can we ever be the sold short or the cheated, we who for every service have long ago been overpaid? ~~ Meister Eckhart
