Contributed by Compilers-R-Us
on Nov 02, 2000 at 00:06 UTC
Q&A
> object-oriented programming
Description: I have a question related to "Calling a method within a double-quoted string" - I would like to call a method within regex match expression, like
print "Matched!" if $myvar =~ /\Q$myob->print\E/;
I can almost do it with 5.005+ as in:
print "Matched!" if $myvar =~ /(?{$myob->escaped})/;
However, I have to pre-escape the return result.
Of course I can use a temporary variable, but that damages the readability.
Unfortunately, I am stuck at 5.004 compatibility and (?{...}) is not supported. Also, I feel that it is my birthright to do this in one line. Is there a one-liner to do this?
Also, is there a reason that the binding is not stronger for '->'?
Answer: How do I call a method within a regular expression (5.004)?
contributed by tedv I'd assume that one reason 5.005 supports ?{} is
that 5.004 needed it. :) Although the object
would definitly have to return a match string,
right?... So if you have an object that just
outputs data, the proper syntax would be:
$myobj->print() =~ /$myvar/
So you might want to/need to swap what's doing the
matching on what. Of course, without context I'm
not sure if this is even possible.
-Ted | Answer: How do I call a method within a regular expression (5.004)?
contributed by Compilers-R-Us
Thanks.
By the way, the (?{}) functionality is listed as 'experimental' in the docs. But yes, hopefully it will remain because people like me want it.
Also, $myobj->print is expected to be a subset of $myvar, in my case, so I can't do it the other way around.
And, I was wrong, (?{}) does have the effect of escaping non-alphanumeric characters in the return value.
Sean
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