### Re: Finding the max()/min()

 on Nov 11, 2004 at 04:55 UTC ( #406924=note: print w/replies, xml ) Need Help??

in reply to Finding the max()/min()

Here's an interesting one that doesn involve a comparison operator (even an obfuscated one):
```(\$x + \$y + abs(\$x - \$y)) / 2
The math behind that is: take the average of the two numbers, and then add half their difference (start half-way between, and then go up by half). So: (x+y)/2 + abs(x-y)/2, and then factor out the division by two.
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Re: Finding the max()/min()
by benizi (Hermit) on Nov 12, 2004 at 21:58 UTC

Very cool. <nitpick>...but there's still a comparison; it's just hidden in the abs() function: (roughly:) abs(x) := x >= 0 ? x : -x.</nitpick>

[OT] Reminds me of a programming assignment where we were supposed to put the square roots of the integers from 1-100 inclusive into two groups with roughly equal sums. I used the fact that sqrt(x) + sqrt(x+3) is very close to sqrt(x+1) + sqrt(x+2) and managed to outperform all the other submissions by several orders of magnitude in both speed and "difference in sum". (Yea math!)

The nitpick is perfectly valid... I almost made a note of it. Of course, it would be possible (though silly) to implement an abs function without a comparison, such as sub abs { sqrt(\$_[0]**2) }.

There's probably some mathematical identity for the abs of the difference of two numbers... but I didn't get enough sleep last night to think about what it might be :-)

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