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Perl: the Markov chain saw

Re^2: Finding the max()/min()

by sleepingsquirrel (Hermit)
on Nov 11, 2004 at 20:03 UTC ( #407168=note: print w/replies, xml ) Need Help??

in reply to Re: Finding the max()/min()
in thread Finding the max()/min()

$x=1; $y=0; $x=-1; $y=2; $x=1.2; $y=2;

-- All code is 100% tested and functional unless otherwise noted.

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Re^3: Finding the max()/min()
by cLive ;-) (Prior) on Nov 11, 2004 at 23:55 UTC
    Ahh, good point ;-)

    Serves me right for trying to be creative on a Windows box sans Perl :)

    cLive ;-)

      This is the variant I found most straightforward to use:
      use List::Util qw[min max]; $m = max(1,2);
      Here you go:

      This is how one can find a maximum number in an array iteratively and recursively in Perl

      #!/usr/bin/perl my (@setOfnumbers); @setOfnumbers = ( 9, 7, 90, 3, 8, 412, 67, 2, 45, 53, 1, 3,89 ); print "Finding maximum number iteratively ", getMaximumNumber(@setOfnumbers) , "\n"; print "Finding maximum number recursively ", findMaximumNumber(@setOfnumbers) , "\n"; #Finding maximum number iteratively sub getMaximumNumber{ my ($maximumNumber); $maximumNumber = @_[0]; foreach(@_){ if ($_ > $maximumNumber){ $maximumNumber = $_; } } return $maximumNumber; } #Finding maximum number recursively sub findMaximumNumber{ my ($maximumNumber); if (@_ == 1){ $maximumNumber = shift(@_); return $maximumNumber; } else{ $maximumNumber = shift(@_); return (findMaximumNumber(@_) > $maximumNumber) ? findMaximumNumber(@_) : $maximumNumber; } }

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