in reply to Equivalency of Code

They are quite clearly not the same.
$x = 3; print $x++;
$x = 3; print $x += 1;
Those two are only the same as regards their effect on $x. The expressions do not *evaluate* to be the same.

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Re^2: Equivalency of Code
by adamk (Chaplain) on Feb 08, 2005 at 03:10 UTC
    No fair!

    HIS code didn't have print statements in it, he was using them as standalone statements. You are testing something different.
    $x = 3; $x++; print $x;
    $x = 3; $x += 1; print $x;
    ...would be more accurate.

    Of course, given problems with operator overloading, they stil arn't actually equal.
      The point is that $x++ and $x += 1 don't just fiddle with the value of $x. Those statements also have values themselves. If a bit of code is to be equivalent to another, then it needs to both have the same side-effects and the same value as the other does.

      I try not to think about operator overloading or tieing :-)

        The statements are presented where in void context - and in void context, there's no return value.