in reply to Re^2: Equivalency of Code
in thread Equivalency of Code
The point is that $x++ and $x += 1 don't just fiddle with the value of $x. Those statements also have values themselves. If a bit of code is to be equivalent to another, then it needs to both have the same side-effects and the same value as the other does.
I try not to think about operator overloading or tieing :-)
|
---|
Replies are listed 'Best First'. | |
---|---|
Re^4: Equivalency of Code
by Anonymous Monk on Feb 08, 2005 at 10:57 UTC |
In Section
Seekers of Perl Wisdom