Re: Regex combining /(foo|bar)/ slower than using foreach (/foo/,/bar/) ???

[samy_kumar]

Hi, I think the problem is with this line.

    my $regex               = qr /(?:$regexstr)/;

because perl compiles this patern again & again in the foreach loop.

    foreach my $stringlength (100,1000,10000,100000)

If you use this pattern

    my $regex               = qr /(?:$regexstr)/o;

instead of

    my $regex               = qr /(?:$regexstr)/;

It will be fast. Since it compiles the pattern only once.

[Roy Johnson]

No, Perl compiles the regex once where it is defined with qr.