note
5mi11er
Forget brute force, using logic to try to create a hand that has no points:<p>
<ul>
<li>All 10, J, Q, K's are eliminated</li><br>
<li>Because 6+9=15 and 7+8=15, we may only take one from each group above 5<br> ie. 6 & 8, 7 & 9 or 8 & 9. 6 & 7 gives a three card run.</li><br>
<li>This means we MUST use at least 2 cards less than 5.</li><br>
<li>A, 2, no 3, that would be a 3 card run, 4, 5<br> can't have a 6, 6+4=10, or 7, 7+2+A=10, or 8, or 9 for same reasons. Dead end.</li><br>
<li> 2, 3, no 4, 5, 6 ok, no 8 allowed, nor 7. Dead end.</li><br>
<li> A, 3, 5, 8, --> Dead end.</li><br>
<li> A, 4, 5, 7, --> Dead end.</li><br>
<li> 2, 4, 5, 7, no 9, 9+2+4=15. Dead end.</li>
</ul><br>this elminates all possible hands.<p>-Scott<p><b>Update:</b> L~R beat me to what this essentially boils down to up in [id://458233|this node] posted just before I'd managed to finish mine.
458233
458233